Найдите допустимые значения переменной х в выражений[tex] \frac{1}{ \sqrt{x+5} } [/tex]. Created by darganyulya2000. algebra-ru

tex]...

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$x+5 \geq 0 \ \Rightarrow \ x \geq -5 \\ \\ \sqrt{x+5} \neq 0 \ \Rightarrow \ x+5 \neq 0 \ \Rightarrow \ x \neq -5 \\ \\ \boxed{x\ \textgreater \ -5}$

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wangross

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ОДЗ:

$\begin{cases} \sqrt{x+5} \neq 0 \\ x+5 \geq 0\end{cases}~\Rightarrow~~~x+5\ \textgreater \ 0~~~ \Rightarrow ~~~x\ \textgreater \ -5$

Ответ: $x\in(-5;+\infty)$

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