Пусть [tex]sin x =3/5[/tex], [tex]x[/tex]∈[tex][ \pi /2;3 \pi /2] [/tex]. Найдите [tex]tg x[/tex]. Created by Dudh. matematika-ru

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Пусть [tex]sin x =3/5[/tex], [tex]x[/tex]∈[tex][ \pi /2;3 \pi /2] [/tex]. Найдите [tex]tg x[/tex]

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Матов

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$cosx=\sqrt{1-\frac{9}{25}}=+-\frac{4}{5}\\\\
cosx=-\frac{4}{5}\\\\
x \in [-\frac{\pi}{2};\frac{3\pi}{2}]\\\\ 
 tgx=\frac{\frac{3}{5}}{-\frac{4}{5}}=-\frac{3}{4}$

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