tex]...

July 2022 1 4 Report

Найти производную функции в точке х нулевое, исходя из ее определения:

y= 1[tex]y= \frac{1}{ (x-2)^{2}}; x_{0}=1 [/tex]

Answers & Comments

CVita $\frac{f'((x-2)^2)}{(x-2)^4}= \frac{-2*(x-2)*f'(x-2)}{(x-2)^4}= \frac{-2*f'(x)*(x-2)}{(x-2)^4}= \frac{-2*(x-2)}{(x-2)^4}= \frac{4-2x}{(x-2)^4}$
подставляем значение $x_{0}$
$\frac{4-2*1}{(1-2)^4}= \frac{4-2}{(-1)^4}=2$

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