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chikipiki
@chikipiki
August 2022
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чему должны быть равны k и p ,чтобы корнями уравнения
[tex]kx {}^{2} + px + 3 = 0[/tex]
были числа 1 и -3?
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snow99
По теореме Виета:
x1 + x2 = -p/k
x1*x2 = 3/k
1 - 3 = -p/k
1*(-3) = 3/k
k = 3 : (-3) = -1
-2 = -p/k
k = -1
p = 2*k = 2*(-1) = -2
ответ: k= -1; p = -2.
1 votes
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Answers & Comments
x1 + x2 = -p/k
x1*x2 = 3/k
1 - 3 = -p/k
1*(-3) = 3/k
k = 3 : (-3) = -1
-2 = -p/k
k = -1
p = 2*k = 2*(-1) = -2
ответ: k= -1; p = -2.