[tex]tg( \frac{5 \pi }{4} + \alpha )(1-sin2 \alpha )-cos2 \alpha =[/tex]. Created by AlisAnarxistka. algebra-ru

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July 2022 1 25 Report

[tex]tg( \frac{5 \pi }{4} + \alpha )(1-sin2 \alpha )-cos2 \alpha =[/tex]

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rskopov Решение:

tg(П/4+a)(1-sin2a)-cos2a=(1-cos(П/2+2a))(1-sin2a)/sin(п/2+2a)-cos2a=(1+sin2a)(1-sin2a)/cos2a-cos2a=(1-sin^2(2a))-cos^2(2a))/cos2a=0.

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