Помогите пожалуйста! 5ый класс! даю 20 БАЛЛОВ!
[tex]7x ^{2} - 1 - (2x + 1) \times (3x - 2) = x^{2} \\ 0 = ( \frac{1}{6} - x) - (x + \frac{1}{3}) + (2x - \frac{1}{3}) \\ 5x - 8x = - (3 + 2x) - (x + 3) \\ (1.6 + x) + (2.4 - 2x) + (x + 7) = 0[/tex]
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