СРОЧНО ДАМ 50 БАЛЛОВ!!![tex] {x}^{2} - x - 56 \leqslant 0[/tex]. Created by youyouyoulol. algebra-ru

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Ответ:

${x}^{2} - x - 56 \leqslant 0 \\ {x}^{2} - x - 56 = 0 \\ D = 1 + 4 \times 56 = 1 + 224 = 225 \\ x_1 = \frac{1 + 15}{2} = 8 \\ x_2 = - 7 \\ + \: \: \: \: \: - \: \: \: \: + \\ - - ( - 7) - - 8 - - > \\ x\in[ - 7;8]$

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