Решить неравенство [tex] lg^{2} x + lg x^{2} -3 \geq 0[/tex]. Created by MaryViolet. algebra-ru

Решить неравенство lg²x+ lg x²-3≥0 ⇔ x>0 и lg²x+2 lg x-3≥0 пусть lg x=t ⇒ t²+2t - 3≥0 t²+2t - 3=0 t1=-3 t2=1 + - +----------------------------------(-3)-------------------------1--------------------------- t≤-3 ∪ t≥11) {lg x≤-3 2 {lg x≥1 {x>0 ∪ {x>0 1) x≤0,001 2) {x≥10 x>0 x∈(0;0,001] { x>0 x∈[10;∞) x∈(0;0,001] ∪[10;∞) Новые вопросы в АлгебраX sin x cos x tg x ctg x π+a - sin a - cos a tg a ctg a π-A sin a cos a - tg a - ctg a 2πτα sin a cos a tg a ctg a 2π-a - sin a cos a - tg a - ctg решите задачу пожалуйстадокажите что для любого натурального числа n справедливо неравенство :1/2^2 + 1/4^2 + 1/6^2 + 1/(2n)^2 + ... < 1/2решите задачу пожалуйстаРешите пожалуйста задачуРешите задачу пожалуйстаРешите задачу пожалуйстаякого найменшого значення набуває вираз і якого значення х х^2-10х+26Решиет уравнение :x^2 + y^2 = 4x^3 + y^3 = -8Решите в целых числах уравнение : xy + 4x - 2y - 7 = 4ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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tex]...

MaryViolet @MaryViolet

July 2022 1 8 Report

Решить неравенство

[tex] lg^{2} x + lg x^{2} -3 \geq 0[/tex]

Answers & Comments

TARTILLO

Verified answer

Решить неравенство
lg²x+ lg x²-3≥0 ⇔ x>0 и lg²x+2 lg x-3≥0

пусть lg x=t ⇒ t²+2t - 3≥0 t²+2t - 3=0
t1=-3 t2=1
+ - +
----------------------------------(-3)-------------------------1---------------------------

t≤-3 ∪ t≥1

1) {lg x≤-3 2 {lg x≥1
{x>0   ∪ {x>0

1) x≤0,001 2) {x≥10
x>0 x∈(0;0,001] { x>0   x∈[10;∞)

x∈(0;0,001] ∪[10;∞)