100⁽²ˣ⁺³⁾×0,1⁽⁴ˣ⁺⁶⁾=10²*⁽²ˣ⁻³⁾×(1/10)²*⁽²ˣ⁺³⁾=10²*⁽²ˣ⁻³⁾×10⁻²*⁽²ˣ⁺³⁾=10⁽⁴ˣ⁺⁶⁾×10⁽⁻⁴ˣ⁻⁶⁾=
=10⁽⁴ˣ⁺⁶⁻⁴ˣ⁻⁶⁾=10⁰=1.
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
100⁽²ˣ⁺³⁾×0,1⁽⁴ˣ⁺⁶⁾=10²*⁽²ˣ⁻³⁾×(1/10)²*⁽²ˣ⁺³⁾=10²*⁽²ˣ⁻³⁾×10⁻²*⁽²ˣ⁺³⁾=10⁽⁴ˣ⁺⁶⁾×10⁽⁻⁴ˣ⁻⁶⁾=
=10⁽⁴ˣ⁺⁶⁻⁴ˣ⁻⁶⁾=10⁰=1.