Решить неравенство:
[tex] 9^{x} - 4 [/tex]·[tex] 3^{x} + 3 \leq 0[/tex]
[tex] 9^{x} - 4 [/tex]·[tex] 3^{x} + 3 \leq 0[/tex]
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9^x-4*3^x+3<=03^x=t
t^2-4t+3<=0
D=16-12=4
x12=4+-2/2=1 3
(t-1)(t-3)<=0
============1=======3=======
++++++++++++ ----------- =+++++
t=[1 3]
3^x>=1
x>=0
3^x<=3
x<=1
x=[0 1]