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sobakazabiyaka
@sobakazabiyaka
July 2022
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Найдите значение выражения
[tex] \frac{cos14а+sin14а+cos42а+sin42а}{ \sqrt{2} cos14а*sin73а} [/tex]
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tseluykoln
((sin14+sin42)+(cos14+cos42))/(√2cos14*sin73)=(2sin28*cos14+2cos28*cos14)/√2cos14*sin73=√2(sin28+cos28)/sin73=√2(sin28+sin62)/sin73=√2*2sin45*
*cos17/sin73=√2*2*√2/2*sin73/sin73=2
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sobakazabiyaka
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Answers & Comments
*cos17/sin73=√2*2*√2/2*sin73/sin73=2