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mkineshma
@mkineshma
August 2022
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найти dy/dx
[tex]y=sin \sqrt{x} /arcsin x^{3} [/tex]
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mikael2
Verified answer
U=sin√x v=arcsinx³ y'=(u/v)'=(1/v²)(u'v-v'u)
u'=cos√x*(1/2√x) v'=1/√(1-x⁶)*3x²
y'=(1/arcsin²x³)*[(0.5*cos√x/√x)arcsinx³-sin√x(3x²/√(1-x⁶))]
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Verified answer
U=sin√x v=arcsinx³ y'=(u/v)'=(1/v²)(u'v-v'u)u'=cos√x*(1/2√x) v'=1/√(1-x⁶)*3x²
y'=(1/arcsin²x³)*[(0.5*cos√x/√x)arcsinx³-sin√x(3x²/√(1-x⁶))]