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AinurB
@AinurB
July 2022
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помогите решить уравнение с модулем [tex]/10x+ 2x^{2} /=12[/tex]
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nikitaaz
X>0
10x+2x^2=12
2x(5+x)=12
2x=12 или 5+x=12
x=6 x=7
----------------------------
x<0
-(10x+2x^2)=12
-10x-2x^2=12
-2x(5+x)=12
-2x=12 или 5+x=12
x=-6 x=7
===========================
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Answers & Comments
10x+2x^2=12
2x(5+x)=12
2x=12 или 5+x=12
x=6 x=7
----------------------------
x<0
-(10x+2x^2)=12
-10x-2x^2=12
-2x(5+x)=12
-2x=12 или 5+x=12
x=-6 x=7
===========================