Как решать?1[tex] 2^{-6} : 2^{7} * 32^{-2} [/tex]Дробь со степенями.. Created by missFr. algebra-ru

tex]Дробь со степенями...

missFr @missFr

June 2022 1 6 Report

Как решать?1[tex] 2^{-6} :
2^{7} * 32^{-2} [/tex]Дробь со степенями.

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inblu

Verified answer

$\frac{2^{-6}}{2^7*32^{-2}}= \frac{2^{-6}}{2^7*(2^5)^{-2}}= \frac{2^{-6}}{2^7*2^{-10}}= \frac{2^{-6}}{2^{7+(-10)}}= \frac{2^{-6}}{2^{-3}}=2^{-6-(-3)}=2^{-6+3}= \\ =2^{-3}= \frac{1}{2^3}= \frac{1}{8}$

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