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rrrrtttt01
@rrrrtttt01
July 2022
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Решите уравнение. Напишите пожалуйста ОДЗ.Чему не равен X[tex] \frac{x-3}{x+2}+ \frac{x+2}{x-3} =4 \frac{1}{4} [/tex]
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Chemist0
Одз:
∈
∞
∞
4 votes
Thanks 2
goroshynka
ОДЗ:х≠-2,х≠3
пусть (x-3)/(x+2)=t,тогда (х+2)/(х-3)=1/t
t+1/t-17/4=0
4t²-17t+4=0
D=225
t=(17-15)/8=1/4 t=(17+15)/8=4
(x-3)/(x+2)=1/4 (x-3)/(x+2)=4
x+2=4x-12 x-3=4x+8
3x=14 3x=-11
x=14/3 x=-11/3
2 votes
Thanks 2
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Answers & Comments
Одз:
∈ ∞ ∞
пусть (x-3)/(x+2)=t,тогда (х+2)/(х-3)=1/t
t+1/t-17/4=0
4t²-17t+4=0
D=225
t=(17-15)/8=1/4 t=(17+15)/8=4
(x-3)/(x+2)=1/4 (x-3)/(x+2)=4
x+2=4x-12 x-3=4x+8
3x=14 3x=-11
x=14/3 x=-11/3