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MizoriesKun
@MizoriesKun
October 2021
2
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пожалуйста срочно с решением !!!!!!!!![tex] \frac{2x-7}{ x^{2} +2x-8 } \geq 1[/tex]
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DariosI
Verified answer
ОДЗ
х²+2х-8=0
D=4+4*8=36
x₁=(-2-6)/2=-4
x₂=(-2+6)/2=2
x∈(-4; -1]∨[1; 2)
7 votes
Thanks 25
MizoriesKun
у вас в интервале описка не -2 а -1
DariosI
Спасибо исправила
MizoriesKun
и вам за помощь
kirichekov
Verified answer
Во вложении-----------------------
6 votes
Thanks 21
MizoriesKun
спасибо огромнейшеее
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Answers & Comments
Verified answer
ОДЗх²+2х-8=0
D=4+4*8=36
x₁=(-2-6)/2=-4
x₂=(-2+6)/2=2
x∈(-4; -1]∨[1; 2)
Verified answer
Во вложении-----------------------