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[tex]( \frac{5}{x-2} -x-2) * \frac{2-x}{x^2-6x+9} [/tex]
[tex]( \frac{5}{x-2} -x-2) * \frac{2-x}{x^2-6x+9} [/tex]
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1) (5 - х(х-2) - 2 (х-2)) / (х-2)= (5-х²+2х-2х+4)/(2-х)=(9-х²)/(2-х)=(3-х)(3+х)/(2-х),2) (3-х)(3+х)/(2-х) * (2-х) /(х²-6х+9)= (3-х)(3+х)(2-х) / (2-х) (3-х) (3-х) = (3+х)/(3-х)
Обратите внимание х² -6х +9 = (х-3)²= (х-3)(х-3) = (3-х)²=(3-х)(3-х)