Упростите эти 2 выражения:
[tex]1) \frac{cos2x}{cosx+sinx} \\ \\ 2)cos2 \alpha +tg \alpha *sin2 \alpha [/tex]
[tex]1) \frac{cos2x}{cosx+sinx} \\ \\ 2)cos2 \alpha +tg \alpha *sin2 \alpha [/tex]
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Answers & Comments
2cos45*sin(45-x)=√2sin(45-x)
2.1-2sin²α+sinα\cosα * 2sinαcosα= 1-2sin²α+2sin²α=1