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βиκτορия
@βиκτορия
November 2021
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ПОМОГИТЕ, ПОЖАЛУЙСТА, СРОЧНО!
Решите неравенство ( 1 - 2 )
a)
[tex]б). 6 x^{2} - 13x - 5 \ \textless \ 0 в). 49 \geq x^{2}[/tex]
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sedinalana
Verified answer
А
(2x-1)/3+(7+5x)/2<4
8x-4+42+30x<24
38x<24-38
38x<-14
x<-7/19
б
6x²-13x-5<0
D=169+120=289
x1=(13-17)/12=-1/3
x2=(13+17)/12=5/2
x∈(-1/3;5/2)
в
49≥x²
x²-49≤0
(x-7)(x+7)≤0x=7 x=-7
x∈[-7;7]
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Answers & Comments
Verified answer
А(2x-1)/3+(7+5x)/2<4
8x-4+42+30x<24
38x<24-38
38x<-14
x<-7/19
б
6x²-13x-5<0
D=169+120=289
x1=(13-17)/12=-1/3
x2=(13+17)/12=5/2
x∈(-1/3;5/2)
в
49≥x²
x²-49≤0
(x-7)(x+7)≤0x=7 x=-7
x∈[-7;7]