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July 2022 1 11 Report

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Тема: Тригонометрические функции удвоенного и половинного аргументов
ДОКАЖИТЕ ТОЖДЕСТВО
[tex]2cos(45 ^{\circ}+a)*cos(45 ^{\circ}-a)=cos 2a[/tex]

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Apofeoz $2\cos(45^\circ+ \alpha )\bullet\cos(45^\circ- \alpha )=\\\\=2(\cos45^\circ\cos \alpha -\sin45^\circ\sin \alpha )(\cos45^\circ\cos \alpha +\sin45^\circ\sin \alpha )=\\\\=2(\frac{\sqrt2}{2}\cos \alpha -\frac{\sqrt2}{2}\sin \alpha )(\frac{\sqrt2}{2}\cos \alpha +\frac{\sqrt2}{2}\sin \alpha )=\\\\=2(\frac{\sqrt2}{2}(\cos \alpha -\sin \alpha) )(\frac{\sqrt2}{2}(\cos \alpha +\sin \alpha) )=\\\\=2\bullet(\frac{\sqrt2}{2})^2(\cos \alpha -\sin \alpha )(\cos \alpha +\sin \alpha )=$

$=\frac{2\bullet2}{4}(\cos^2 \alpha-\sin^2 \alpha )=\cos^2 \alpha -\sin^2 \alpha =\cos2 \alpha .$

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