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[tex]\frac{cos 105 cos 5 + sin 105 cos 85}{sin 195 cos 5 + cos 195 sin 185}[/tex]
1) cos105cos5 + sin105cos85 = cos105cos(90-85) + sin105cos85 =
=cos105sin85 + sin105cos85 = sin(105+85) = sin190
2)sin195cos5 + cos195sin185 = sin195cos5 + cos195sin(180+5) =
=sin195cos5 - cos195sin5 = sin(195-5) = sin190
sin190/sin190 = 1
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Answers & Comments
1) cos105cos5 + sin105cos85 = cos105cos(90-85) + sin105cos85 =
=cos105sin85 + sin105cos85 = sin(105+85) = sin190
2)sin195cos5 + cos195sin185 = sin195cos5 + cos195sin(180+5) =
=sin195cos5 - cos195sin5 = sin(195-5) = sin190
sin190/sin190 = 1