Знайдіть значення виразу:[tex](3 {a}^{2} - 8ab ) + {a}^{2} - (7ab + 4 {a}^{2} )[/tex],якщо [tex]a = 2 \frac{1}{17} [/tex][tex]b = - 2 \frac{3}{7} [/tex]. Created by alengricenko. algebra-ru

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$(3a^{2} -8ab)+a^{2}-(7ab+4a^{2})=3a^{2} -8ab+a^{2}-7ab-4a^{2}=-15ab\\\\-15ab=-15\cdot 2\dfrac{1}{17}\cdot(-2\dfrac{3}{7})=\dfrac{15\cdot 35\cdot 17}{17\cdot 7}=15\cdot 5=\boxed{75}$

OblivionFire

Ответ:

(3а^2-8ab)+a^2-7ab-4a^2=3a^2-8ab+a^2-7ab-4a^2=0-15ab=-15ab ; при а=2 1\17 и b=-2 3\7 ;

-15*2 1\17 *(-2 3\7)= -15*35\17*(-17\7)= 15*35\17*17\7=15*35*1\7=15*5=75

Объяснение:

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