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July 2022 1 20 Report

Нужна помощь с заданием

Нужно избавиться от иррациональности:
[tex]{\frac{3-\sqrt{3} }{3+\sqrt{3} } }[/tex]

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$\frac{3-\sqrt{3}}{3+\sqrt{3}}=\frac{(\sqrt{3})^{2}-\sqrt{3}}{(\sqrt{3})^{2}+\sqrt{3}}=\frac{\sqrt{3}(\sqrt{3}-1)}{\sqrt{3}(\sqrt{3}+1)}=\frac{\sqrt{3}-1}{\sqrt{3}+1} =\frac{(\sqrt{3}-1)(\sqrt{3}-1)}{(\sqrt{3}+1)(\sqrt{3}-1)}=\frac{3-2\sqrt{3}+1}{(\sqrt{3})^{2}-1}=\frac{4-2\sqrt{3}}{2}=2-\sqrt{3}\\\\Otvet:\boxed{2-\sqrt{3}}$

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Answers & Comments

Verified answer

pomogitepozhalujstas zadaniyamidayu 100 ballov1 esli lezvie bezopasnoj britvy

oooochen srochno nuzhna pomosh izmenenie sily toka katushki v kolebatelnom konture

m kolebletsya s amplitudoj 2 sm chemu ravna maksimalnaya kineticheskaya energiya gr

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ochen srochno nuzhna pomosh s zadachej dayu 98 ballov najti kineticheskuyu energiyu e

dobrogo vremeni sutoksrochno nuzhna pomosh s zadachej dayu 98 ballov zaryazhennaya ch

dobrogo vremeni sutok pomogite pozhalujsta s zadaniem nuzhno opredelit napravleni

pozhalujstapomogite s zadachej dayu 98 ballov na provodnik s tokom 2a i dlinoj ak

dobrogo vremeni sutoknuzhna pomosh s dannym zadaniempolozhitelno zaryazhennaya cha

pochemu v obektive fotoapparata kraya linzy okrasheny v fioletovyj cvet obyasnite

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