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[tex](ctg^2a-tg^2a)* \frac{1}{ctg^a-1} = \frac{1}{cos^2a} [/tex]
[tex](ctg^2a-tg^2a)* \frac{1}{ctg^a-1} = \frac{1}{cos^2a} [/tex]
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Answers & Comments
(ctg^4a-1)/ctg²a *1/(ctg²a-1)=(ctg²a-1)(ctg²a+1)/ctg²a*1/(ctg²a-1)=
=(ctg²a+1)/ctg²a=1/sin²a:cos²a/sin²a=1/cos²a