Помогите дописать интеграл: [tex]\int\limits {\frac{dx}{1-5sin^2x} } = \int\limits {\frac{dx}{sin^2x(\frac{1}{(sin^2x}-5) } } = \left \{ {{\frac{1}{sin^2x} =1+ctg^2x} = .....[/tex] . Ответ: [tex]\frac{1}{4} ln |\frac{1+2tgx}{1-2tgx}|+C[/tex]
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