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pikulaura
@pikulaura
July 2022
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При каком значении m уравнение
[tex] \frac{6x-m}{2} = \frac{7mx+1}{3} [/tex]
имеет корень равный нулю?
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Gerren
Пропорция
3(6x-m)=2(7mx+1)
18x-3m=14mx+2
18x-14mx-3m-2=0
-14mx-3m=2-18x
m=2-18x/(-14x-3)
x=0 m=-2/3
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Answers & Comments
3(6x-m)=2(7mx+1)
18x-3m=14mx+2
18x-14mx-3m-2=0
-14mx-3m=2-18x
m=2-18x/(-14x-3)
x=0 m=-2/3