Значение выражения [tex]\frac{5}{12} lk +(-\frac{1}{6} lk)+lk+(4lk-14lk)[/tex] равно...
1) 4lk
2) 5lk
3) [tex]3\frac{1}{4} [/tex]lk
4) [tex]4\frac{6}{12}[/tex]lk
1) 4lk
2) 5lk
3) [tex]3\frac{1}{4} [/tex]lk
4) [tex]4\frac{6}{12}[/tex]lk
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