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[tex] {x}^{2} + {x}^{2} = 24 \sqrt{2} [/tex]
Помогите найти Х
[tex] {x}^{2} + {x}^{2} = 24 \sqrt{2} [/tex]
Помогите найти Х
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Ответ:
x1 = -2*2^(1/4)*sqrt(3)
x2 = 2*2^(1/4)*sqrt(3)
Объяснение: