ОДЗ:
Ответ: x=60
ОДЗ: х-10>0. x>10
㏒5(x-10)=㏒5 (5)²+ ㏒5(2)
㏒5(x-10)=㏒5 (25)+㏒5 (2)
x-10=25*2
x-10=50
x=50+10
x=60
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ОДЗ:
Ответ: x=60
Verified answer
ОДЗ: х-10>0. x>10
㏒5(x-10)=㏒5 (5)²+ ㏒5(2)
㏒5(x-10)=㏒5 (25)+㏒5 (2)
x-10=25*2
x-10=50
x=50+10
x=60