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mishhenkokatya
@mishhenkokatya
July 2022
1
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Вычислите предел, используя правило Лопиталя
а) lim x->0 arcctgbx/cx
b) lim x->∞ 7n²-6n+5/3-2n-n²
c) lim x->0 sin6x+sin5x/tg2x
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NNNLLL54
Verified answer
P.S. Если
, то правило Лопиталя применять не надо.
1 votes
Thanks 1
Tanda80
arcctg(0)=Pi/2, a не бесконечность
NNNLLL54
Наоборот, arcctg(pi/2)=0 , а при x-->0 справа или слева arcctgx --> (+/-)беск .
NNNLLL54
Извиняюсь, это сtg(pi/2)=0, a arcctg0=pi/2...
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Answers & Comments
Verified answer
P.S. Если , то правило Лопиталя применять не надо.