Lim стремиться к нулю. (sin5x)/(tg2x). Created by ololo2510. algebra-ru

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ololo2510 @ololo2510

June 2022 1 13 Report

Lim стремиться к нулю. (sin5x)/(tg2x)

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$\lim_{x \to 0} \frac{sin5x}{tg2x}= \lim_{x \to 0} ( \frac{sin5x}{5x}* \frac{5x}{1}* \frac{cos2x}{sin2x})=\\\\=\lim_{x \to 0} ( \frac{sin5x}{5x}* \frac{5x}{1}* \frac{cos2x}{ \frac{sin2x}{2x} *2x})=\\\\= \lim_{x \to 0} ( \frac{sin5x}{5x}* \frac{5}{1}* \frac{cos2x}{ 2*\frac{sin2x}{2x} }) =1* \frac{5}{2}* \frac{1}{1}=2,5$

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