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Chabarovav
@Chabarovav
July 2022
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Точка движется прямолинейно по закону:S(t)=x^3-3x^2+2x.Вычислите ее ускорение в конце 5-ой секунды
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sedinalana
Verified answer
V(t)=s`(t)=3x²-6x+2
a(t)=v`(t)=6x-6
a(5)=30-6=24
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Verified answer
V(t)=s`(t)=3x²-6x+2a(t)=v`(t)=6x-6
a(5)=30-6=24