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19761649
@19761649
August 2021
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точка В( х. 3) А(-2 .1) Найти х
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Джанджа
• B (x; 3) ; A (-2; 1) C =?
x(C) = (x(A) + x(B))/2 =
x(C) = (-2+x)/2 =
Составляем Уравнение:
x= (-2+x)/2
2x = -2+x
2x - x = -2
2x - (1)x = -2
x = -2
x(C) = (x(A)+x(B))/2 =
x(C) = (-2+(-2))/2 = -2
x(C) = -2
y(C) = (y(A) + y(B))/2 =
y(C) = (1+3)/2 = 4/2 = 2
y(C) = 2
A = [-2; 1]
B = [-2; 3]
C = [-2; 2]
DG_Janja
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Answers & Comments
x(C) = (x(A) + x(B))/2 =
x(C) = (-2+x)/2 =
Составляем Уравнение:
x= (-2+x)/2
2x = -2+x
2x - x = -2
2x - (1)x = -2
x = -2
x(C) = (x(A)+x(B))/2 =
x(C) = (-2+(-2))/2 = -2
x(C) = -2
y(C) = (y(A) + y(B))/2 =
y(C) = (1+3)/2 = 4/2 = 2
y(C) = 2
A = [-2; 1]
B = [-2; 3]
C = [-2; 2]
DG_Janja