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ArtyomO
@ArtyomO
August 2021
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Тригонометрия, 10 класс
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harutyunyan46
ПО условия задача a+b=p/2 , то b=p/2-a .(cos(3p/2-(p/2-a)) *tga/2 - cos(p-(p/2-a)))/(sin(3/2p-a)-sin(p-a)*tg(p/4-(p/4-a/2))= (cos(p+a)*tga/2- cos(p/2+a))/ (-cosa-sina*tga/2) = (-cosa*tga/2 +sina)/ (-cosa-sina*tga/2)= (-cosa*sina/2 +sina*cosa/2)/ (-cosa*cosa/2-sina*sina/2)= sin(a-a/2)/-(cosa*cosa/2+sina*sina/2)= - sina/2/cosa/2= -tga/2 .
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