Ответ:
дано
m(Na2SO3) = 7,1 g
W(NaOH) = 20%
----------------------
m(ppa NaOH) - ?
2NaOH+SO2-->Na2SO3+H2O
M(Na2SO3) = 126 g/mol
n(Na2SO3) = m/M = 7.1 / 126 = 0.056 mol
2n(NaOH) = n(Na2SO3) = 0.056 mol
n(NaOH) = 2*0.056 = 0.112 mol
M(NaOH) =40 g/mol
m(NaOH)= n(NaOH) * M(NaOH) = 0.112 * 40 = 4.48 g
m(ppa NaOH) = m(NaOH) * 100% / W(NaOH) = 4.48 * 100 / 20 = 22.4 g
ответ 22.4гр
Объяснение:
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Answers & Comments
Ответ:
дано
m(Na2SO3) = 7,1 g
W(NaOH) = 20%
----------------------
m(ppa NaOH) - ?
2NaOH+SO2-->Na2SO3+H2O
M(Na2SO3) = 126 g/mol
n(Na2SO3) = m/M = 7.1 / 126 = 0.056 mol
2n(NaOH) = n(Na2SO3) = 0.056 mol
n(NaOH) = 2*0.056 = 0.112 mol
M(NaOH) =40 g/mol
m(NaOH)= n(NaOH) * M(NaOH) = 0.112 * 40 = 4.48 g
m(ppa NaOH) = m(NaOH) * 100% / W(NaOH) = 4.48 * 100 / 20 = 22.4 g
ответ 22.4гр
Объяснение: