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gattibn94
@gattibn94
July 2022
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У трикутнику ABC вiдомо, що AC = 6√3, <B = 60, <A = 45. Знайдiть сторону BC.
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cayman73
По теореме сину
сов BC/sin45°=AC/sin60°
BC/(√2/2)=(6√3)/(√3/2)
2BC/√2=12
BC/√2=6
BC=6√2
7 votes
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Answers & Comments
BC/(√2/2)=(6√3)/(√3/2)
2BC/√2=12
BC/√2=6
BC=6√2