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GARY45
@GARY45
July 2022
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1) найдите корень квадратного трехчлена х^2-4х-1
3)сократите дробь у^2-4/у^2+3у+2
3)с^2-2с√10+7
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erzhan9210
1) x²-4x-1=0
D=4²-4(-1)=16+4=20
√D=√20=2√5
x=(4±2√5)/2 = 2±√5
2) y²-4= (y-2)(y+2)
y²+3y+2 = (y+2)(y+1)
(y²-4)/(y²+3y+2) = (y-2)/(y+1)
3) c²-2√10c+7=0
D=(2√10)²-4*7 = 40-28 = 12
√D=√12=2√3
C=(2√10±2√3)/2 = √10±√3
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Answers & Comments
D=4²-4(-1)=16+4=20
√D=√20=2√5
x=(4±2√5)/2 = 2±√5
2) y²-4= (y-2)(y+2)
y²+3y+2 = (y+2)(y+1)
(y²-4)/(y²+3y+2) = (y-2)/(y+1)
3) c²-2√10c+7=0
D=(2√10)²-4*7 = 40-28 = 12
√D=√12=2√3
C=(2√10±2√3)/2 = √10±√3