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cos4α+4cos2α+3
cos4α=2cos^2 (2α) -1
2cos^2(2α)-1+4cos2α+3 = 2cos^2α+4cos2α+2 = 2(cos^2 (2α)+2cos2α+1) = 2(cos2α+1)^2
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cos4α+4cos2α+3
cos4α=2cos^2 (2α) -1
2cos^2(2α)-1+4cos2α+3 = 2cos^2α+4cos2α+2 = 2(cos^2 (2α)+2cos2α+1) = 2(cos2α+1)^2