Упростить и вычислить. Created by Sky09. algebra-ru

Упростить и вычислить...

Sky09 @Sky09

September 2021 1 34 Report

Упростить и вычислить

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Artem112

Verified answer

$( \frac{ \frac{1}{a}-a }{( \sqrt[3]{a}+a^{- \frac{1}{3}} +1)(a^{\frac{1}{3}}+a^{- \frac{1}{3}} -1)} } +a^{\frac{1}{3}} )^{-3}
$

$\sqrt[3]{a} =b$

$( \frac{ \frac{1}{b^3}-b^3 }{( b+ \frac{1}{b} +1)(b+ \frac{1}{b} -1)} } +b} )^{-3}=
( \frac{ \frac{1-b^6}{b^3}}{( b+ \frac{1}{b} )^2-1^2} } +b} )^{-3}=
\\\
( \frac{ \frac{1-b^6}{b^3}}{b^2+ \frac{1}{b^2}+2-1} } +b} )^{-3}=
( \frac{ 1-b^6}{b^3(b^2+ \frac{1}{b^2}+1)} } +b} )^{-3}=
\\\
( \frac{ 1-b^6}{b^5+ b+b^3} } +b} )^{-3}=
( \frac{ 1-b^6+b(b^5+ b+b^3)}{b^5+ b+b^3} }} )^{-3}=
$

$=( \frac{ 1-b^6+b^6+ b^2+b^4}{b^5+ b+b^3} }} )^{-3}=
( \frac{ 1+ b^2+b^4}{b^5+ b+b^3} }} )^{-3}=
\\\
( \frac{ b^5+ b+b^3}{1+ b^2+b^4} }} )^3=
( \frac{ b(b^4+ b^2+1)}{b^4+ b^2+1} }} )^3=b^3=( \sqrt[3]{a} )^3=a=1.75$

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Verified answer

tex]...

zadanie tipa s6 tolko punktvna doske vypisany vse naturalnye chisla ot 1 d

(5x-4a)<4...

tex]...

sin20*sin40*sin60*sin80 sin10*sin30*sin50*sin70...

kto pomozhet s zadachkoj po fizike

skolkimi sposobami mozhno razbit chislo 64 na 10 naturalnyh slagaemyh celyh g

tex na prostoe nechyotnoe r raven 1

drobno irracionalnoe neslozhnoe

pri kakom znachenii parametra k uravnenie x42k8x2k28k150 imeet 4 reshe

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sin20sin40sin60sin80 sin10sin30sin50sin70...