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inkognitous
@inkognitous
November 2021
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DedushkaBake
По формуле sin(a-b)=sinacosb-cosasinb
=2(sin(π/6)cosa-cos(π/6)sina)-cosa+(√3)sina=
2(1/2)cosa-2((√3)/2)sina-cosa+(√3)sina=
cosa-(√3)sina-cosa+(√3)sina=0
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Answers & Comments
=2(sin(π/6)cosa-cos(π/6)sina)-cosa+(√3)sina=
2(1/2)cosa-2((√3)/2)sina-cosa+(√3)sina=
cosa-(√3)sina-cosa+(√3)sina=0