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Барби67
@Барби67
August 2022
1
9
Report
Упростите выражение.
cos(90градусов-a)-1 2cos(270градусов+a)-1
__________________ - ____________________ +
sin(180градусов-a)+1 cos^2(180градусов+а)
+ctg^2(90градусов+а)-3
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TARTILLO
Verified answer
Cos(90°-a)-1 2cos(270°
+a)-1
___________ - ______________ +
ctg^2(90°+а)-3 =
sin(180
°-a)+1 cos^2(180°
+а)
=(
sin(a)-1)/(sin(a)+1) - (2sin(a)-1)/ cos^2(а) +tg^2(а)-3 =
=(sin(a)-1)/(sin(a)+1) - (2sin(a)-1)]/cos^2(а) +sin^2(а)/ cos^2(а)-3=
=(sin(a)-1)/(sin(a)+1) +[sin^2(а)-2sin(a)+1]/[1-sin^2(а)] -3=
=[(sin(a)-1)²-((sin(a)-1)²]/(sin^2(a)+1)-3=0-3=-3
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Answers & Comments
Verified answer
Cos(90°-a)-1 2cos(270°+a)-1___________ - ______________ + ctg^2(90°+а)-3 =
sin(180°-a)+1 cos^2(180°+а)
=(sin(a)-1)/(sin(a)+1) - (2sin(a)-1)/ cos^2(а) +tg^2(а)-3 =
=(sin(a)-1)/(sin(a)+1) - (2sin(a)-1)]/cos^2(а) +sin^2(а)/ cos^2(а)-3=
=(sin(a)-1)/(sin(a)+1) +[sin^2(а)-2sin(a)+1]/[1-sin^2(а)] -3=
=[(sin(a)-1)²-((sin(a)-1)²]/(sin^2(a)+1)-3=0-3=-3