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DrDre69
@DrDre69
October 2021
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m11m
По действиям:
1)
12^n * 27
=
(3*4)^n * 3³
=
3^n * 4^n * 3³
=
3^(n-1) * 4^(n+1) 3^(n-1) * 4^(n+1) 3^(n-1) * 4^(n+1)
=
3^(n+3) * 4^n
= 3^(n+3-n+1) * 4^(n-n-1) = 3⁴ * 4⁻¹ =
3⁴
3^(n-1) * 4^(n+1) 4
2) √(3⁴/4) =
√3⁴
=
9
√4 2
3)
9
+ 4 ¹/₂ =
9
+
9
= 9
2 2 2
4)√9 =3
Ответ: 3.
1 votes
Thanks 1
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Answers & Comments
1) 12^n * 27 = (3*4)^n * 3³ = 3^n * 4^n * 3³ =
3^(n-1) * 4^(n+1) 3^(n-1) * 4^(n+1) 3^(n-1) * 4^(n+1)
=3^(n+3) * 4^n = 3^(n+3-n+1) * 4^(n-n-1) = 3⁴ * 4⁻¹ = 3⁴
3^(n-1) * 4^(n+1) 4
2) √(3⁴/4) = √3⁴ = 9
√4 2
3) 9 + 4 ¹/₂ = 9 + 9 = 9
2 2 2
4)√9 =3
Ответ: 3.