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J0VEVIP
@J0VEVIP
June 2022
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Упростите выражение !!!!
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Lesben
(2x/(x-2) - 1/(x+2)):(6x²+9x+6)/(x²-4)=
=(2x(x+2)-(x-2)/((x+2)(x-2)) . (x+2)(x-2)/3(2x²+3x+2)=
=(2x²+4x-x+2)/3(2x²+3x+2)=(2x²+3x+2)/3(2x²+3x+2)=1/3
Otvet: 1/3 , x≠2,x≠-2
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Answers & Comments
=(2x(x+2)-(x-2)/((x+2)(x-2)) . (x+2)(x-2)/3(2x²+3x+2)=
=(2x²+4x-x+2)/3(2x²+3x+2)=(2x²+3x+2)/3(2x²+3x+2)=1/3
Otvet: 1/3 , x≠2,x≠-2