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denis012
@denis012
August 2022
1
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в 500 грамм воды растворили 250 мл хлороводорода какова массовая доля хлороводорода в растворе?
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iriska114
500 + 250 = 750.
0. 1. x
500*0 +250=750x
x =0,3333(33,33%)
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0. 1. x
500*0 +250=750x
x =0,3333(33,33%)