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yseroshtanova
@yseroshtanova
July 2022
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В геометрической прогрессии b12=128 , b15=1024. Найдите знаменатель этой прогрессии
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KsyshaSmir
B15=b12*q3
1024=128*q3
q3=8
q=2
5 votes
Thanks 5
2407Alexa
Bn=b1*q^n-1n=12 и n=15b12=b1*q^11b15=b1*q^14q³=1024/128q³=8=2³q=2b1=b12/q^11b1=128/2^11=128/2048b1=0,0625
4 votes
Thanks 4
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Answers & Comments
1024=128*q3
q3=8
q=2