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Данякеп
@Данякеп
September 2021
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oganesbagoyan
Verified answer
Task/26548536
---------------------
25.
√12*cos²5π/12 =2√3 *(1+cos2*5π/12) /2 =√3 *(1+cos5π/6) =√3 *
(
1+cos(π -π/6)
)
√
3 *(1- cosπ/6) = √3 *(1-√3 /2 )
=
√3 - 1,5 .
------------
26.
√3 -
√12sin
²5π/12
=√3 - 2√3( 1 -cos2*5
π/12)
/
2 =
√3 - √3( 1 -cos5
π/6)=
√3cos5π/6 = √3cos(π - π/6) = -√3cosπ/6 =
-
√3*(
√3)/2 = -3/2
= -1,5.
------------
27.
50sin19°cos19° / sin38° =25*2sin19°cos19° / sin38° =25*sin2*19°
/
sin38
° =
25*sin38°
/
sin38
°
= 25.
2 votes
Thanks 1
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Answers & Comments
Verified answer
Task/26548536---------------------
25.
√12*cos²5π/12 =2√3 *(1+cos2*5π/12) /2 =√3 *(1+cos5π/6) =√3 *(1+cos(π -π/6))
√3 *(1- cosπ/6) = √3 *(1-√3 /2 )= √3 - 1,5 .
------------
26.
√3 - √12sin²5π/12 =√3 - 2√3( 1 -cos2*5π/12) / 2 =√3 - √3( 1 -cos5π/6)=
√3cos5π/6 = √3cos(π - π/6) = -√3cosπ/6 = -√3*(√3)/2 = -3/2 = -1,5.
------------
27.
50sin19°cos19° / sin38° =25*2sin19°cos19° / sin38° =25*sin2*19°/ sin38° =
25*sin38°/ sin38° = 25.