всё в скрине помогите пжл. Created by northkavkaz. algebra-ru

всё в скрине помогите пжл...

northkavkaz @northkavkaz

July 2022 1 15 Report

всё в скрине помогите пжл

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sedinalana

Verified answer

2^x=a
(a²-8a+7)/(a²-5a+4)-(a-9)(a-4)-1/(a-6)≤0
a²-8a+7=0
a1+a2=8 U a1*a2=7⇒a1=1 U a2=7
a²-5a+4=0
a1+a2=5 U a1*a2=4⇒a1=1 U a2=4
(a-1)(a-7)/(a-1)(a-4)-(a-9)(a-4)-1/(a-6)≤0
(a-7)/(a-4)-(a-9)(a-4)-1/(a-6)≤0
a≠1⇒2^x≠1⇒x≠0
[(a-6)(a-7-a+9)-a+4]/(a-6)(a-4)≤0
(2a-12-a+4)/(a-6)(a-4)≤0
(a-8)/(a-6)(a-4)≤0
a=8 a=6 a=4
_ + _ +
------------------(4)------------(6)--------------[8]------------
a<4⇒2^x<4⇒x<2 U x≠0
6<a<8⇒6<2^x≤8⇒log(2)6<x≤3
x∈(-∞;0) U (0;2) U (log(2)6;3]

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