1) sin120= sin(90 + 30) = sin90cos30 + cos90sin30 = 1*√3/2 + 0*1/2 = √3/2
2) cos210= cos(180 + 30) = cos180cos30 – sin180sin30 = (-1)* √3/2 – 0*1/2 = -√3/2
3) sin20cos25+ cos20sin25 = sin(20 + 25) = sin45 = √2/2
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
1) sin120= sin(90 + 30) = sin90cos30 + cos90sin30 = 1*√3/2 + 0*1/2 = √3/2
2) cos210= cos(180 + 30) = cos180cos30 – sin180sin30 = (-1)* √3/2 – 0*1/2 = -√3/2
3) sin20cos25+ cos20sin25 = sin(20 + 25) = sin45 = √2/2