вычислить предел функции1)lim x²-4x-21 2)lim 2x x⇒₇ x-7 x⇒бесконечность x-1. Created by MavrinaUyla. algebra-ru

вычислить предел функции1)lim x²-4x-21 2)lim 2x x⇒...

MavrinaUyla @MavrinaUyla

October 2021 1 9 Report

вычислить предел функции

1)lim x²-4x-21 2)lim 2x
x⇒₇ x-7 x⇒бесконечность x-1

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ewgenijbark

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$lim_{x\to\7} \frac{x^2-4x-21}{x-7}=lim \frac{(x-7)(x+3)}{x-7}=lim(x+3)=7+3=10 \\ \lim_{x \to \infty} \frac{2x}{x-1}= \lim_{x \to \infty} \frac{2x}{x(1- \frac{1}{x}) }= \lim_{x \to \infty} \frac{2}{1- \frac{1}{x} }= \frac{2}{1-0} =2$

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