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@777555321
July 2022
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Вычислить y'(-2), если y=(5x+3)^5
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Сюррикен
Y'= 5(5x+3)^4
y'(-2)= 5* (-10+3)^4= 5* 49^2=2401*5= 12005
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Lesben
Y=(5x+3)ˇ5
y´=5(5x+3)ˇ4 . (5x+3)´=25(5x+3)ˇ4
y´(-2)=25(-10+3)ˇ4=25.(-7)ˇ4=25.49.49=60025
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Answers & Comments
y'(-2)= 5* (-10+3)^4= 5* 49^2=2401*5= 12005
y´=5(5x+3)ˇ4 . (5x+3)´=25(5x+3)ˇ4
y´(-2)=25(-10+3)ˇ4=25.(-7)ˇ4=25.49.49=60025